A sum of money is divided among 3 boys so that the first get one half of it and the second one third of the remainder what fraction of the first boys is the third boys share
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Hope u like my process
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=> Let the total sum of money be Rs x
=> 1st boy gets half of it.. i.e. Rs x/2
=> Remaining sum = Rs(x-x/2) = Rs x/2.
=> 2nd boy gets ⅓rd of remainder...
So he actually gets = Rs ⅓ of x/2.
So the third one would have (1-⅓) of the first ones share.
So the third one will have ⅔ rd of the first boys share.
________________________
Hope this is ur required answer
Proud to help you
=====================
=> Let the total sum of money be Rs x
=> 1st boy gets half of it.. i.e. Rs x/2
=> Remaining sum = Rs(x-x/2) = Rs x/2.
=> 2nd boy gets ⅓rd of remainder...
So he actually gets = Rs ⅓ of x/2.
So the third one would have (1-⅓) of the first ones share.
So the third one will have ⅔ rd of the first boys share.
________________________
Hope this is ur required answer
Proud to help you
Namisha01:
hi !
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