Math, asked by daljitrahon02, 3 months ago

A sum of money is divided among A, B, C and
D in the ratio 3:5:7:11. If the share of C is Rs.
1668 more than the share of A, then what is
the total amount of money of B and D
together?​

Answers

Answered by ram07091999
0

Answer:

6672

Step-by-step explanation:

Let A, B, C, D get 3x, 5x, 7x, 11x.

Given C got 1668 more than A, so 7x - 3x = 1668

4x = 1668

x = 417

Total amount of B+D = 16x = 16*417 = 6672

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