A sum of money is divided among a, b, c and d in the ratio of 3 : 5 : 9 : 13 respectively. If the share of c is `, 2412 more than the share of a, then what is the total amount of money of b and d together ?
a. ` 4422
b. ` 6030
c. ` 4824
d. None
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let the ratio is x
A:B:C:D--3x:5x:9x:13x
now given condition
c sahre is 2412 more than a share
A+2412=C
3x+2412=9x.....3x-9x=-2412
6x=2412
x=2412/6=402
now putting value of x in ratios
3*402=1206 ----a shares
5*402=2010----b shares
9*402=3618----c shares
13*402=5226----d shares
now adding B and D shares
2010+5226=7236
so option D none is the right answer....
A:B:C:D--3x:5x:9x:13x
now given condition
c sahre is 2412 more than a share
A+2412=C
3x+2412=9x.....3x-9x=-2412
6x=2412
x=2412/6=402
now putting value of x in ratios
3*402=1206 ----a shares
5*402=2010----b shares
9*402=3618----c shares
13*402=5226----d shares
now adding B and D shares
2010+5226=7236
so option D none is the right answer....
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