Question

A sum of money is divided among three persons P, Q and R in the ratio 3 : 7 : 11. If R has $168 more than P, find the total sum of money.

Answer 1

Answer:

Correct option is

B

Rs 6672

Let the shares of A,B,C,D, be Rs3x,Rs5x,Rs7xandRs11x respectively.

Then, 7x−3x=1668⇒4x=1668⇒x=417∴B

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share+D

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share=5x+11x=Rs16x=16×417=Rs6672

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Step-by-step explanation:

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