Question

A sum of money is invested for 2 years at the rate of 12% per annum compounded
annually. If it was invested at simple interest, the interest would be ₹72 less than the
compound interest. Find the sum of money.
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Answer 1

Answer:

Compound Interest

${ \tt \pink {A \: = p \times{ (1 + \frac{12}{100} ) }^{2} }}$

${ \tt \pink {A \: = p \times{ (1 + \frac{12}{100} ) }^{2} - p }}$

Simple interest

$\tt \pink { i = \frac{p \times t \times r}{100} }$

Difference is 72

${ \tt \pink {A \: = p \times{ (1 + \frac{12}{100} ) }^{2} - p - \frac{p \times t \times r}{100} = 72 }}$

$\tt \green {p = 5000 \: rs }$

Answer 2

Answer :-
P=5000rs
hope this helps you