Math, asked by shivam58, 1 year ago

a sum of money is invested for 3 years at a rate of 10% interest compounded annually. if the sum of money grows by Rs 5296 then find the sum of money invested.

Answers

Answered by bhattisingh111
23
LET THE AMT=a
i.e. a+5296=a(110/100)(110/100)(110/100)
i.e. a+5296=1331a/1000
i.e. 1000a+5296000=1331a
i.e. 331a=5296000
i.e. a=5296000/331=16000

shivam58: bhai agar amount=a hai to ap a+5296=(110/100)(110/100)110/100) kaise likhe ho..
bhattisingh111: a=principal amt, then maturity value=principal amt + intt=a+5296=a(1+r/100)^t
Answered by jitendraampg
8

Answer:

Step-by-step explanation:

LET THE AMT=a

i.e. a+5296=a(110/100)(110/100)(110/100)

i.e. a+5296=1331a/1000

i.e. 1000a+5296000=1331a

i.e. 331a=5296000

i.e. a=5296000/331=16000

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