A sum of money is lent at 8%p.a C. I. If the interest for the second year exceeds that for the first year by Rs96, find the sum of (money)
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Answer:
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Let P=Rs x,R=8% then
Then interest for the first year=
100
x×8×1
=
100
8x
Then Principal foe the second year=x+
100
8
x=Rs
100
108
x
hence interest for the second year=
100
100
108
x×8×1
=Rs.
10000
864x
According to the question
⇒
10000
864x
=
100
8x
+96
⇒
10000
864x
−
100
8x
=96
⇒
10000
864x−800x
=96
⇒
10000
64x
=96
⇒64x=96×10000
⇒x=
64
96×10000
⇒x=15000
Hence the sum=Rs. 15000
Thank you.
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