A sum of money is lent at 8% p. a compound interest. If the interest for the second year exceeds that for the first year by $96,find the sum of money.
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Step-by-step explanation:
ASSUME P = 100$
GIVEN:
- RATE = 8% p.a.
- CI 2 - CI 1 = 96$
WE KNOW THAT
- CI 1 = (PNR)/100
- = ( 100 × 1 × 8)/100
- = 8$ ------- 1
- CI 2 = (PNR)/100
- ( 108 × 1 × 8)/100
- = 8.64$
CI 2 - CI 1 = 0.64$
USING UNITARY METHOD:
DIFFERENCE. PRINCIPLE
0.64. 100
96. X
USING DIRECT VARIATION, WE GET:
0.64x = 9600
therefore,
ANSWER) x = 15000$
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