Math, asked by Priyanshijha3161, 9 months ago

A sum of money is lent at 8 per annum compound interest. if the interest for the 2nd yr exceeds that for the first year by 32

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Answered by musharraf786azam
2

Answer:

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MATHS

A sum of money is lent at 8% per anuum compound interest. If the interest for the second year exceeds that for the first year by Rs. 96, find the sum money.

December 26, 2019

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Sumita Franklin

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ANSWER

Let P=Rs x,R=8% then

Then interest for the first year=

100

x×8×1

=

100

8x

Then Principal foe the second year=x+

100

8

x=Rs

100

108

x

hence interest for the second year=

100

100

108

x×8×1

=Rs.

10000

864x

According to the question

10000

864x

=

100

8x

+96

10000

864x

100

8x

=96

10000

864x−800x

=96

10000

64x

=96

⇒64x=96×10000

⇒x=

64

96×10000

⇒x=15000

Hence the sum=Rs. 15000$$

Step-by-step explanation:

I hope this is helpful for you

Answered by anup15416668nnRitik
2

Answer:

by this method your answer come

Step-by-step explanation:

Answers

For 1st year p=rupees x .Rate=8% Time =1year

interest =x*8*1/100

=0.08x

and amount =x+0.08x=1.08x

For 2nd year P=1.08x rupees Rate=8% Time= 1 year

Interest =1.08x*8*1/100

=0.0864x

Amount =1.08x+0.0864x

=1.8864 x

0.0864x-0.08x=96

x=15000

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