A sum of money is lent at 8% per annum compound interest. If the interest for the second year exceeds that for the first year by ₹96, find the sum of money.
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Answer:
Let P=Rs x,R=8% then
Then interest for the first year=100x×8×1=1008x
⇒Let P=Rs x,R=8% then
Then interest for the first year=100x×8×1=1008x
Then Principal foe the second year=x+1008x=Rs100108x
hence interest for the second year=100100108x×8×1=Rs.10000864x
According to the question
⇒10000864x=1008x+96
⇒10000864x−1008x=96
⇒10000864x−800x=96
⇒1000064x=96
⇒64x=96×10000
⇒x=6496×10000
⇒x=15000
Hence the sum=Rs. 15000$$
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