A sum of money is lent out at compound interest for two years
at 20%
p.a.,
C.I. being
reckoned yearly. If the same sum of money is lent out at compound interest at the
same rate percent per annum, C.I. being reckoned half-yearly, it would have fetched
482 more by way of interest. Calculate the sum of money lent out.
Answers
Answer:
A sum of money is lent out at compound interest for two years at 20% p.a., being reckoned yearly.
0
votes
1.2k views
asked Feb 4, 2019 in Class X Maths by muskan15 (-3,443 points)
A sum of money is lent out at compound interest for two years at 20% p.a., being reckoned yearly. If the same sum of the money was lent Gut at compound interest of the same rate of percent per annum C.I., being reckoned half yearly would have fetched Rs. 482 more by way of interest. Calculate the sum of money lent out.
compound interest
Please log in or register to answer this question.
1 Answer
0
votes
answered Feb 4, 2019 by aditya23 (-2,151 points)
Let the principle be ₹ 100
For first case r = 20% p.a.
n = 2 years
Difference between two interest
= ₹ 46.41 - ₹ 44.00 = ₹ 2.41
If differences is ₹ 2.41 then principal be ₹ 100
If differences is ₹ 482 then principal will be
= ₹ 100/2.41 x 482
= ₹ 100 x 482/241 x 100
= ₹ 100 x 100 x 2
= ₹ 20000
∴ Sum is ₹ 20000.
Step-by-step explanation:
hope it helps you
thanku
Let the principle be ₹ 100
For first case r = 20% p.a.
n = 2 years
A= P (1+r/100) n
= 100(1+20/100) 2
= 100(1+1/5) 2
= 100(6/5) 2
= 100×6×6/5×5
= 3600/25
= ₹144
CI= A-P
= 144-100= ₹44
For second case
r= 20%p.a.= 20/2 half- yearly
=10% semi annual
Time= 2 years = 4 half years
A = P (1+r/100)n
= 100(1+10/100) 4
= 100(1+1/10) 4
= 100(11/10) 4
= 100×11×11×11×11/10×10×10×10
= 121×121/10×10
= 14641/100
= 146.41
CI = A-P
= 146.41-100
= 46.41
Difference between two interest
= ₹ 46.41 - ₹ 44.00 = ₹ 2.41
If differences is ₹ 2.41 then principal be ₹ 100
If differences is ₹ 482 then principal will be
= ₹ 100/2.41 x 482
= ₹ 100 x 482/241 x 100
= ₹ 100 x 100 x 2
= ₹ 20000
∴ Sum is ₹ 20000.