Math, asked by Supuriya9841651930, 11 months ago

A sum of money is placed at SI for 3 yrs at 10% per annum and then amount is invested for 2 yrs at same rate at CI.If the total amount of 5 yrs became Rs.471900,what was the sum? Find it.

Answers

Answered by bansalshubhamm
0

Answer:

300000

Step-by-step explanation:

see attachment

Attachments:
Answered by durgeshshrivastav205
0

prices = Rs 3,00,000

Step-by-step explanation:

case i

Time = 3yrs

Rate = 10%

Let price = Rs x

simple interest = ?

we know,

simple interest = PTR/100

= x ×3×10/100

= 30x/100

=0.3x .........1

case ii

New ,

Price = 0.3x + x

p = Rs 1.3x

Time (T) =2yrs

Rate (R) =10%

5yrs after amount (Pt) = Rs471900

Now,

471900 =1.3x(1 +10/100)^2

or, 471900 = 1.3x (1.1)^2

or 471900 =1.3×1.21x

I. e x = 471900/1.573

so x =300,000

thus the prices be Rs 300,000.

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