Question

A sum of money is shared among three brothers. The eldest receives of it and the 7/13 next receives 2/3 of the remainder. If the youngest brother receives $6, find the sum of
money shared​

Answer 1

Answer:

Let the total money be x, which 7s shared between three brothers

The eldest receives 7/13 of it

7/13 of x

= 7x/13

and the next receives 2/3 of the remainder

Remaining money after eldest share

x - 7x/13

=(13x - 7x)/13

= 6x/13

Next get 2/3 of 6x/13

= 2/3 × 6x/13

= 12x / 39

the youngest brother received $6

7x/13 + 12x/39 + $6 = x

(21x + 12x)/39 = x - 6

33x/39 = x - 6

Cross multiplications

33x = 39 (x - 6)

33x = 39x - 234

33x - 39x = - 234

-6x = -234

x = 234/6

x = 39

The total money is $39

Answer the total money is $39

Now checking the correctness of answer by distributing the derived money $39 among three brothers.

Eldest received 7/13 of 39 = $21

Second brother received 2/3 of (39 - 21) = 2/3 × 18 =$12

Youngest brother received $6

Total money = $21 + $12 + $6= $39

Means answer is correct

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Answer 2

7/13 + 4/13 = 11/13, thus the third brother gets 2/13. Iftheyoungest received $6, then half of that, or $3, is the equivalent of half of 2/13, or 1/13. If 1/13 =$3, then 13/13 = 13x$3 = $39. The sum of the money being shared is $39.

Step-by-step explanation:

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