A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?
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Answered by
1
Answer:
let the money be x
Share of D is 3/14x
Share of C is 4/14x
4/14x = 3/14x + 1000
(1/14)x = 1000
x = 14000
Sum of money is 14000Rs
Share of b is 2/14x == 2/14× 14000 == 2000Rs
Answered by
1
Answer:
A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, then the of B's is Rs 2000.
Step-by-step explanation:
A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3.
If the common multiple is x, then the shares of A, B, C, and D be Rs.5x, Rs.2x, Rs.4x, and Rs.3x respectively.
As per the given condition
C gets Rs. 1000 more than D, means difference is 1000.
4x−3x=1000
x=1000
∴ B's share =Rs.2x = Rs.(2×1000) = Rs.2000.
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