Question

A sum of money is to be distributed among A,B,C in the ratio 6:19:7 if C gives RS 200 from his share to B the ratio A,B and C becomes 3:10:3 what is the total sum​

Answer 1

★Given:-

• A sum of money is to be distributed among A,B,C in the ratio 6:19:7.
• If C gives Rs. 200 from his share to B the ratio A,B and C becomes 3:10:3.

★To find:-

• The total sum.

★Solution:-

Given ratio : 6:19:7

Let,

• A's share = 6x
• B's share = 19x
• C's share = 7x

Then,

Total sum = Sum of share's of A,B&C

➜6x + 19x + 7x

➜32x

As C gives Rs.200 to B,B's share increases by 200 and C's share decreases by 200.

Then we'll have,

• A's share = 6x
• B's share = 19x + 200
• C's share =7x - 200

Given that the ratio becomes 3:10:3.Therefore,

➜6x:(19x + 200):(7x - 200)  = 3:10:3

As the ratio becomes 3 : 10 : 3,the final share of A & C are equal. Hence,we can write the equation as,

 ➜6x = 7x - 200

➜6x - 7x = -200

➜-x = -200

➜x = 200

Total sum :-

➜6x + 19x + 7x

➜32x

➜32(200)

➜Rs.6400

Hence, the total sum is Rs.6400.

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