Question

A sum of money is to be distributed between Ajay and Sanjay in the proportion of 7:11 respectively. Sanjay gets R 6000 more than Ajay. How much did Ajay get? ​

Answer 1

11x-7x=4x

4x=6000

x=6000/4

=1500

Then Ajay get..1500*7=Rs10500

Answer 2

Ajay got Rs 10500 .

Explanation:

Given : A sum of money is to be distributed between Ajay and Sanjay in the proportion of 7:11 respectively.

Let Ajay gets amount 7x and Sanjay get 11x.

Sanjay gets R 6000 more than Ajay.

$\Rightarrow 11x-7x=6000$

$\Rightarrow 4x=6000$

$\Rightarrow x=1500$  [Divide both ides by 4]

The amount Ajay received = 7 (1500) = Rs 10500

Hence, Ajay got Rs 10500 .

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