A sum of money lent at SI amounts to 7500 Rs in 5 years and 9500 Rs in 9 years. Find the sum of money and the rate of the interest.
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Answer:
let X be the sum of money and let r be the rate of interest.
then, Amount A = X(1+rt)
when amount is 7500
=>7500 = X(1+5r)
=7500/X = 1+5r
=>5r = (7500/X)-1
=>r= (1500/X)-0.2-----------(1)
when amount is 9500
=>9500 = X(1+9r)
=>9500/X = 1+9r
=>9r=(9500/X)-1
=>r = (9500/(9X))-(1/9)----------(2)
comparing eqn 1 and 2
(1500/X)-0.2 = (9500/(9X))-(1/9)
=>1500-0.2X = (9500-X)/9
=>13500-1.8X = 9500-X
=>13500-9500 = 1.8X-X = 0.8X
=>4000 = 0.8X
=>X = rs 5000/-
from eqn 1
r = (1500/5000)-0.2 = 0.1 =10/100
=>r = 10%
So sum of money is Rs 5000/- and rate of interest is 10%
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