Math, asked by balkishanmor79, 6 months ago

A sum of money lent at simple interest amounts to 17,145 in 3 years and to 19,575 in 5 years. Find the sum and the rate of interest.​

Answers

Answered by sharmaa8466
16

Answer:

Let the sum be "p" and rate of interest is "r"

Amount (A) = Principle (P) + Simple Interest (I)

So, Simple Interest = Amount - Principal

Given that a sum of money lent at simple interest amounts to rupees 17145 in 3 years and to rupees 19575 in 5 years

From this, we can say,

Amount = 17145 in 3 years:

So, S.I for 3 years = 17145 - p ---- eqn 1

Amount = 19575 in 5 years:

So, S.I for 5 years = 19575 - p ----- eqn 2

Subtracting (2) and (1), we get,

S.I for 2 years = 19575 - p -17145 + p

S.I for 2 years = 2430

Now, SI for 1 year = \frac{2430}{2} = 1215

2

2430

=1215

Let us calculate S.I for 3 years = 3 x 1215 = 3645

Now put S.I for 3 years = 3645 in eqn1,

3645 = 17145 - p

p = 13500

Hence sum "p" = 13500

Calculation of Rate of interest:

S.I = \frac{P \TIMES N \TIMES R}{100}S.I=

100

P\TIMESN\TIMESR

Where,

"p" = principal sum

"r" = rate of interest

"n" = number of years

We know that S.I for 3 years = 3645 and p = 13500

Here n = 3 years

\begin{gathered}3645 = \frac{13500 \times 3 \times r}{100}\\\\3645 = 135 \times 3 \times r\\\\r = 9\end{gathered}

3645=

100

13500×3×r

3645=135×3×r

r=9

Hence rate of interest = 9%

Step-by-step explanation:

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Answered by rishisai521229
3

Answer:

854 rupees for 3 years in 5years 874 rupees

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