a sum of money lent out at simple interest Doubles itself in 8 years,
find:
i) the rate of interest
ii) in how many years will the sum become triple of itself at the same rate percent.
Answers
Answered by
2
Let principal deposited be x, since amount is double interest will also be x now,
SI=100*x divided by (8*x)=12.5
SI=100*x divided by (8*x)=12.5
SolvingBuddy:
i know i am asking for. 2nd part
Answered by
6
Let principal be x. If principal is x , then A=2x ,si=2x-x=x. R= 100*si/p*t
R= 100 * x/x*8=12.5
Second
Let p be x so,A=3x,SI=2x
T=2*100/x* 12.5=16 years
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