A sum of money p was invested for 3 years at SI and after 3 years P double and rate increased by 2% for the next two years . the total interest was 1360 , the same interest was received when time was 34/3 yeas find P?
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Step-by-step explanation:
Principle= Rs 4000
time=2 year
Rate=10%
Compound interest=P×(1+r)
n
−P
I=P{(1+r)
n
−1}
I=4000(1+.10)
2
−1
I=4000(1.21−1)
I=840
AS per question,
Simple interest=840/2=420=PRT/100
S0, I=420=P×0.08×3
I=1750Rs
Answer (C) 1750 Rs
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