Math, asked by shahid9832, 5 months ago

A sum of money p was invested for 3 years at SI and after 3 years P double and rate increased by 2% for the next two years . the total interest was 1360 , the same interest was received when time was 34/3 yeas find P?​

Answers

Answered by ayankumar18435
0

Step-by-step explanation:

Principle= Rs 4000

time=2 year

Rate=10%

Compound interest=P×(1+r)

n

−P

I=P{(1+r)

n

−1}

I=4000(1+.10)

2

−1

I=4000(1.21−1)

I=840

AS per question,

Simple interest=840/2=420=PRT/100

S0, I=420=P×0.08×3

I=1750Rs

Answer (C) 1750 Rs

Answered by pratyusha99
0

Answer:

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Step-by-step explanation:

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