a sum of money placed at C.I. double itself in 4 yrs. Calculate the time taken to amount it 8 times.
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Given :-
- Sum of money becomes 2 times in 4 years.
- Rate is compounded Annually.
To Find :-
- in how many years it will be 8 Times. ?
Solution :-
Let ,
→ Principal = P
→ Rate % = R
→ Time = 4 years .
→ Amount = 2P
So,
→ P [ 1 + (R/100) ]⁴ = 2P
→ [1 + (R/100) ]⁴ = 2 ------------------- Equation (1).
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Now, Let it becomes 8 times in T years.
So,
→ P [ 1 + (R/100) ]^T = 8P
→ [ 1 + (R/100) ]^T = 8
→ [ 1 + (R/100) ]^T = (2)³
Now, Putting value of 2 from Equation (1) Here , we get,
→ [ 1 + (R/100) ]^T = { [ 1 + (R/100) ]⁴}³
→ [ 1 + (R/100) ]^T = [ 1 + (R/100) ]^12
Now, we know that, if a^b = a^c Than, b = c,
So,
→ T = 12 Years (Ans).
Hence, The Sum of Money will be 8 Times in 12 years.
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