Question

A sum of money placed at



c.I. Doubles itself 4 yrs. In how many years will it amount to eight times itself.

Answer 1

Answer :

Formula: n2=n1^(t2/t1)

n=number of times

t=years

n2 = 8 i.e. 2^3

n1 = 2 (doubles)

t2 = x

t1 = 4

n2=n1^(t2/t1)

2^3 = 2^(x/4)

3 = x/4

3*4 = x

x = 12 years

$\rule{200}{2}$