Question

A sum of money put a 11% per annum amount to ₹4491in
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Answer 1

Answer:

Rs:4788.PLEASE MARK ME AS THE BRAINLIEST

Step-by-step explanation:

As we know that SI = P x R x T /100 (Where P = Principal Amount, R = Rate of Interest and T = Time).

Let us assume that the principal amount be Rs. X.

Then the SI will be Rs (4491 - X)

Rate of interest = 11% and Time = 2 yrs 3 months = 2 yrs 3/12 = 2.25 yrs.

So (4491 - X) = X * 11 * 2.25/100

(4491 - X) = 24.75X/100

449100 - 100X = 24.75X

-100X - 24.75X = - 449100

-124.75X = -449100

X = - 449100/- 124.75 = 3600.

So the Principal amount is equal to Rs. 3600.

Now the second part of the problem:

SI = PxRxT/100 (Where P = Rs 3600, R = 11% and T = 3yrs)

SI = 3600 x 11 x 3/100 =Rs. 1188.

So the amount will be Rs. (3600 + 1188) = Rs. 4788.

Ans: Rs. 4788.