Question

A sum of money put at 11% per annum amounts to Rs. 4491 in 2 years 3 months . what will it amounts to in 3 years at the same rate ?​

Answer 1

T = 2 years 3 months =2+

12

3

=2+

4

1

=

4

9

Let P be the principle amount

A=P+

100

PRT

4491=P(1+

4×100

11×9

)

4491=P(1.2475)

⇒ P = 3600 Rs.

SI=

100

3600×11×3

=1188Rs.

A = 3600 + 1188 = 4788 Rs.

Answer 2

Answer:

After 3 years the amount will be Rs. 4788.

Step-by-step explanation:

Given that,

Amount = Rs. 4491

Rate of Interest = 11%

Time = 2 years 3 months = 2 yrs 3/12 year = 2 year + 1/4 year = 9/4 year.

As we know that,

$S.I.=\frac{P*R*t}{100}$

$(4491-x)=\frac{x*11*2.25}{100}\\\\=>449100-100x=24.75x\\\\=>124.75x=449100\\\\=>x=\frac{449100}{124.75}\\\\=>x=3600$

So the Principal amount is equal to Rs. 3600.

Now the second part of the problem:

$\\S.I.=\frac{P*R*t}{100}\\\\(Where\:P=Rs.\:3600,\:R=11\%\:and\:T=3yrs.)\\=>S.I.=\frac{3600*11*3}{100}\\\\=>S.I.=Rs.\:1188$

So the amount will be Rs. (3600 + 1188) = Rs. 4788.

After 3 years the amount will be Rs. 4788.

_____________

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