Question

A sum of money put out a compound
interest increased by Rs. 180 at the end first year and Rs
188.10 at the end of second year. Find the rate percent and
the sum.​

Answer 1

Answer:

Let S be the sum

S+180= S(1+0.01r) This gives 0.01rS = 180

S+188.10 = S(1+0.01r)^2 This gives

S- S(1+0.01r)^2 = -188.10

S[1-(1+0.01r)^2]=-l88.10

S[(1+1+0.01r)(1-1-0.01r)=-188.10

S(2+0.01r)(-0.01r)=-188.10

180(2+0.01r)=-188.10

2+0.01r=188.10/180 = 1.045

0.01r= 1.045-2 = negative

So it is a wrong question