a sum of money trebles itself in 15 years 6 months. in how many years would it double itself
Answers
Answered by
7
Let sum = x.
Then
S.I.=2x and Time = 31/2years
..˙..˙ Rate = (100×2x/x×2/31)%(100×2x/x×2/31)%
=(40031)%(40031)%
Now, Sum=x, S.I.=x
and Rate = (400/31)%(400/31)%
..˙..˙ Time = (100×x/x×31/400)(100×x/x×31/
400)year
=7 years 9 months.
Then
S.I.=2x and Time = 31/2years
..˙..˙ Rate = (100×2x/x×2/31)%(100×2x/x×2/31)%
=(40031)%(40031)%
Now, Sum=x, S.I.=x
and Rate = (400/31)%(400/31)%
..˙..˙ Time = (100×x/x×31/400)(100×x/x×31/
400)year
=7 years 9 months.
Answered by
3
Hey Mate ⭐✋⭐
Here's ur answer ⤵
Let sum = x Then, S.I. = 2x.
Time = 15 1/2 years= 31/2 years
Rate= (100 * 2x / x * 31/2) %
=400/31%
Now, sum = x, S.I. = x, Rate = 400/31%
Time= 100*x/ x* 400/31
=31/4 years
= 7 years 9 months.
Hope it helps you! ヅ
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