Math, asked by kaleemsarwar6, 1 year ago

a sum of money trebles itself in 15 years 6 months. in how many years would it double itself

Answers

Answered by darsh755
7
Let sum = x.
Then 
S.I.=2x and Time = 31/2years
..˙..˙ Rate = (100×2x/x×2/31)%(100×2x/x×2/31)%
           =(40031)%(40031)%
Now,       Sum=x,    S.I.=x
and      Rate = (400/31)%(400/31)%
..˙..˙ Time = (100×x/x×31/400)(100×x/x×31/
400)year
            =7 years 9 months.
Answered by Anonymous
3

Hey Mate ⭐✋⭐

Here's ur answer ⤵

Let sum = x Then, S.I. = 2x.

Time = 15 1/2 years= 31/2 years

Rate= (100 * 2x / x * 31/2) %

=400/31%

Now, sum = x, S.I. = x, Rate =  400/31%

Time= 100*x/ x* 400/31

=31/4 years

= 7 years 9 months.

Hope it helps you! ヅ

✪ Be Brainly ✪


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