A sum of money was distributed among three children Laxmi,Priya and Rani respectively. Laxmi and Priya received 1/6 and 1/8 of the sum and the remaining amount was given to Rani. If Ranireceived 1950 more than Laxmi, then how much should Rani giveto Priya so that Rani has twice as much as Priya?
Answers
Solution :-
Let us assume that, total sum of money was Rs. 24x .
So,
→ Laxmi received = (1/6) * 24x = Rs. 4x
→ Priya received = (1/8) * 24x = Rs. 3x
then,
→ Rani received = 24x - (4x + 3x) = Rs. 17x
A/q,
→ Rani received - Laxmi received = Rs. 1950
→ 17x - 4x = 1950
→ 13x = 1950
→ x = 150
therefore,
→ Rani received = 17x = 17 * 150 = Rs. 2550
→ Priya received = 3x = 3 * 150 = Rs. 450
Now, let Rani gave Rs. y to priya so that Rani has twice as much as Priya .
then,
→ (2550 - y) = 2(450 + y)
→ 2550 - y = 900 + 2y
→ 2y + y = 2550 - 900
→ 3y = 1650
→ y = Rs. 550 (Ans.)
Hence, Rani should give Rs. 550 to Priya so that Rani has twice as much as Priya .
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