Question

a sum of money was distributed equally in class of boys. had there be 10 boys more , each would have received a rupee less and had there been 15 fewer, each would have received 3 rupee more. find the sum of money and number of boys

Answer 1

Let the sum of rupee be x and no of boys be y then each boy get x/y now if the no of boys increased by 10 each boy get x/(y+10) = (x/y)-1 => x/(y+10) = (x-y)/y ............,.(1) now case 2nd if no of boys decrease by 15 each boy get x/(y-15)= (x/y) +3 => x/(y-15) = (x+3y)/y ...........(2) solve the equations and get the answer

Answer 2

Let the sum of rupee be x
 no of boys be y
then each boy get x/y
now if the no of boys increased by 10 each boy get x/(y+10) = (x/y)-1 => x/(y+10) = (x-y)/y .........(1)
now case 2nd if no of boys decrease by 15 each boy get x/(y-15)= (x/y) +3 => x/(y-15) = (x+3y)/y ...........(2)
solve the equations and get the answer