Question

A sum of rs. 1,300 is divided amongst p, q, rand s such that (p's share)/(q's share)=(q's share)/(r's share)=(r's share)/(s's share)=2/3then p's share is

Answer 1

`P : Q = 2 : 3, Q : R = 2 : 3 = 3/2 xx 2 : 3/2 xx 3 = 3 : 9/2`. `:. P : Q : R = 2 : 3 : 9/2 = 4 : 6 : 9` And, `R : S = 2 : 3 : 9/2 xx 2 : 9/2 xx 3 = 9 : (27)/2` `:. P : Q : R : S = 4 : 6 : 9 : (27)/2 = 8 : 12 : 18 : 27`. `:. P's share = Rs. (1300 xx 8/(65))` `= Rs. 160`.

Answer 2

Answer:

P = 540

Step-by-step explanation:

P/Q = Q/R = R/S = 2/3 (Given)

Since the ratio is a constant proportion, P, Q, R and S are in a GP series

Total sum = 1300

Number of terms = 4

Common ratio = 2/3

Find the first term:

Sn = a(1 - rⁿ)/(1 - r)

1300 = P(1 - 2/3⁴) / (1 - 2/3)

1300= 65/27 (p)

P = 1300 ÷ 65.27

P = 540

Answer: P = 540