Question

A sum of Rs. 1000 is invested for 5 years at rate of 12% per annum. Find compound interest and due amount.

@NeonSparkles ​

Answer 1

Given:-

• Principal (P) = ₹1000
• Time or period (n) = 5 years
• Rate (R) = 12%

Find:-

• The amount and compound interest.

Solution:-

A = P (1 + R/100)^n

$= > 1000( \frac{100 + 12}{100} ) ^{5}$

$= > 1000( \frac{112}{100})^{5}$

$= > 1000 \times \frac{112}{100} \times \frac{112}{100} \times \frac{112}{100} \times \frac{112}{100} \times \frac{112}{100}$

$= > 1762.32$

CI = A - P

=> ₹ 1762.32 - ₹ 1000

=> ₹ 762.32

Heading:-

The amount is ₹ 1762.32 and compound interest is ₹762.32

Answer 2

hey mate here is your ans

principle=1000₹

time=5 years

Rate=12%

compound interest=?

amount=?

amount=P(100+R/100)^T

1000(100+112/100)^5

amount=1762.34168

compound internet=amount-principle

compound interest=₹762.34108