Question

A sum of Rs-1000 is lent for 1 year at the rate of 7% p.a. Find the interest and the amount​

Answer 1

$\LARGE{\bf{\underline{\underline{GIVEN:-}}}}$

• Principle (P)= 1000 Rs.
• Rate (R) = 7%.
• Time (T) = 1 year.

$\LARGE{\bf{\underline{\underline{TO:FIND:-}}}}$

• The interest (I).
• The amount (A).

$\LARGE{\bf{\underline{\underline{SOLUTION:-}}}}$

We know that Amount:

$\sf{\red{I=\dfrac{PRT}{100}}}$

Substituting the values:

$\sf I=\dfrac{1000 \times 7 \times 1 }{100}$

$\boxed{\sf{\blue{ I=70 \ Rs.}}}$

We know that amount = P+I

Amount = 1000+70

Amount = 1070 Rs.

Answer 2

Question

a sum of rupees thousand is land for one year at the rate of 7% p a find the interest and the amount ?

Solution :-

Given,

• principal = ₹1000
• rate per annum = 7%
• time = 1 year

To find the interest ;

we know that to find interest we have to use the below formula ;

$\bold = > \green{ \frac{prt}{100} }$

Or

principal x rate X time / 100 .

now putting the value in the formula we get ;

$= > \pink{ \frac{1000 \times 7 \times 1}{100} }$

$= > \pink{ \frac{ \cancel{1000} \times 7 \times 1}{ \cancel{100}} }$

$= > \pink{ \frac{10 \times 7 \times 1}{1} }$

$= > \pink{70}$

so the interest is 70 .

Now ,

to find the amount we have to use the below formula

$\bold \green{ = > amount = principal +interest}$

now putting the amount in the given formula we get ;

$\red{ = > a = 1000 + 70}$

$= > \red{a = 1070}$

Hence, the amount is ₹1070 and the interest is 70 .