A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest. What is the rate of interest?
Answers
Answered by
6
R = rate of simple interest (no compound)
At the beginning: 12500
After 1 year: 12500 + R × 12500 = 12500(1 + R)
After 2 years: 12500(1 + R) + R × 12500 = 12500(1 + 2R)
After 3 years: 12500 × (1 + 3R)
After 4 years: 12500 × (1 + 4R)
After n years: 12500 × (1 + nR)
12500 (1 + 4R) = 15500
1 + 4R = 15500 ÷ 12500
1 + 4R = 1.24
4R = 1.24 - 1
4R = 0.24
R = 0.06 = 6%
At the beginning: 12500
After 1 year: 12500 + R × 12500 = 12500(1 + R)
After 2 years: 12500(1 + R) + R × 12500 = 12500(1 + 2R)
After 3 years: 12500 × (1 + 3R)
After 4 years: 12500 × (1 + 4R)
After n years: 12500 × (1 + nR)
12500 (1 + 4R) = 15500
1 + 4R = 15500 ÷ 12500
1 + 4R = 1.24
4R = 1.24 - 1
4R = 0.24
R = 0.06 = 6%
Answered by
15
here,
p = 12500
t = 4
I = Interest amount = total amount - principle amont
= 15500 - 12500
= 3000
let, rate of interest = r
p × t× r / 100 = 3000
⇒(12500 × 4 × r ) / 100 = 3000
⇒500 r = 3000
⇒ r = rate of interest = 3000/500 = 6 %
p = 12500
t = 4
I = Interest amount = total amount - principle amont
= 15500 - 12500
= 3000
let, rate of interest = r
p × t× r / 100 = 3000
⇒(12500 × 4 × r ) / 100 = 3000
⇒500 r = 3000
⇒ r = rate of interest = 3000/500 = 6 %
Grzesinek:
p × t × r / 100 is only to equal 15500 - 12500 = 3000, not 15500
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