A sum of Rs 1200 was lent at a simple interest rate of 6 1/4 % p.a. and another sum of Rs 1000 was lent at a simple interest rate of 813 % p.a. After how many years will the amounts in the two investments be equal?
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Answer:
Step-by-step explanation:
Let the second part be Rs. x. Then first part is Rs. (1200−x)
So interest on first part =
100
(1200−x)×5×2
=
10
(1200−x)
And interest on second part =
100
(x)×6×2
=
25
3(x)
Now, according to question:
10
(1200−x)
+
25
3x
=128
Taking LCM and solving further, we get:
⇒5(1200−x)+6x=128×50
⇒6000−5x+6x=6400
⇒x=400.
So, second part is Rs. 400.
Hence, first part is (1200−x)=Rs. 800
,Hence ratio of first part to second part is 800:400=2:1
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