A sum of Rs. 12500 is distributed among A, B, C & D such that A gets Rs. 800 more than what B gets, C get twice of what B get and D get Rs. 900 more than what A gets. The ratio in which D, C, B & A receive the sums is:
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Let’s solve in the old fashion way,
A = B+C , B = 125+C , C , D=C
So 750 is distributed among all 4,
so, A+B+C+D = 750
(B+C) + (125+C) + (C) + (C) = 750
((125+C) +C) + (125+C) + 2C = 750
250 + 5C = 75
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