Question

A sum of Rs. 1360 has been divided among A, B and C such that A gets 2/3 of what B gets and B gets 1/4 of what C gets. B's share is:
A.Rs. 120
B.Rs. 160
C.Rs. 240
D.Rs. 300

Answer 1

let C's share be RS x
B gets 1/4 of x=1/4x
A gets 2/3 of 1/4x
=1/6x
x+1/4x+1/6x=1360
L.CM 12
12x+3x+2x/12=1360
17x/12 =1360
17x=1360×12
x=1360×12/17
x=960
c get. x= 960
b gets 1/4×960
240

Hence,Answer to your question is 240.

Hope it helped you

Thanks......❤

Answer 2

The B's share is Rs 240

Step-by-step explanation:

Let us assume that B's share is Rs  x.

Given that,

Total amount of sum = Rs 1360

Writing equations for the given condition,

A gets 2/3 of B can be written as A= $\frac{2}{3}$ × B

=> A= $\frac{2}{3}$ × $x$  [∵ B's share = Rs x]

B gets 1/4 of C can be written as B = $\frac{1}{4}$ × C

=>  $x= \frac{1}{4}$ × C

=> ∴ $C=4x$

We know that,

A + B + C = 1360

Substituting the values of A,B and C in the above relation,

=> $(\frac{2}{3} x) + x + (4x) =1360$

Taking LCM as 3, we get

=> $\frac{2x+3x+12x}{3} =1360$

=> $\frac{17x}{3} =1360$

=> $x=\frac{1360 * 3}{17}$

=> x = 80 × 3

∴ x=240Rs

Hence B's share is Rs 240