A sum of Rs 140 is divided into two parts. If the greater part is Rs 20 more than the double of smaller part, find the parts of the sum.
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Answered by
11
Let smaller part be x
x+20+2x=140
3x=120
x=40
Larger part=40(2)+20=100
x+20+2x=140
3x=120
x=40
Larger part=40(2)+20=100
Answered by
12
Step-by-step explanation:
- let the greater part be X and the smaller part be Y
- so the equation will be
- X+Y=140 AND X=20+2Y
- Substituting the value of equation 2 in equation 1
- 20+2Y+Y=140
- 20+3Y=140
- 3Y=140-20
- 3Y=120
- Y=120/3
- Y=40 and X=20 +2(40)=20+80=100
- SO X=100 AND Y=40
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