Question

A sum of Rs 1536 put at compound interest, amounts to Rs 1632 in one year. How much would it amount to in the second year?

Answer 1

Answer:

Given:

Principal - ₹ 1536

Amount - ₹ 1632

CI - ₹ 96

Time - 1 year

Rate - ?

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To Find:

Rate of the Compound interest - ?

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Formula Used:

$\bf\green{ SI = \frac{prt}{100} }$

$\bf\green{ 96 = \frac{1536 \times r \times 1}{100} }$

$\bf\green{ 96 \times 100= 1536 \times r }$

$\bf\green{ 9600= 1536 \times r }$

$\bf\green{ \frac{9600}{1536} = r }$

$\bf\green{ 6 \frac{1}{4} = r }$

$\bf\purple{\underline{Compound\: Interest: -}}$

$\bf\pink{ A= p(1 + \frac{r}{100} )^{n}}$

$\bf\pink{ 1632= 1536(1 + \frac{25}{400} )^{2}}$

$\bf\pink{ 1632 - 1536 = ( \frac{425}{400} )^{2} }$

$\bf\pink{ 96 = ( \frac{17}{16} )^{2} }$

$\bf\pink{ 96 = \frac{17}{16} \times \frac{17}{17} }$

$\bf\pink{ 96 \times 16 \times 16= 17 \times 17 }$

$\bf\pink{ \frac{24576}{289} = a }$

$\bf\red{ 85.03 = Rs. }$

Hope it will be helpful :)....✍️

Answer 2

Answer:

Answer is here:-

First thing is that the compound interest of 1 year and the simple interest of 1 year are equal.

P=1536 N=1 R=x A=1632

A-P=SI=96

SI=PNR /100

96=1536*1*x/100

96*100/1536=x

6.25=x = Rate

A =[1536(1+6.25/100)^2]

A = 1536*6.5/4*6.5/4

A =Rs 4056

by simple interest

SI = 1536*2*6.25/100

SI=192

A= 1536+192=1728ans.

Step-by-step explanation:

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