Math, asked by pgpankaj5979, 1 year ago

A sum of rs. 1890 is to be used to give seven cash prizes to students of a school Fri their overall academic performance. if each prizes is rs. 50 less than its preceding prize, find the value of each of the prizes

Answers

Answered by YourPalNurav
133
The problem is related to AP
Sum of 7 terms=1890
Common difference =d=-50

We know the formula
S(n) = n/2 × [2a+(n-1) d ]
S(7) = 7/2 × [2a+(7-1)*-50]
1890=7/2 × [2a+(6*-50)]
1890*2=7 × [2a-300]
3780=14a-2100
3780+2100=14a
5880=14a
a=5880/14
a=420

Hence required AP is
a, a+d, a+2d, a+3d, a+4d, a+5d, a+6d
Since d is negative AP becomes
a, a-d, a-2d, a-3d, a-4d, a-5d, a-6d
Substituting a&d we get,
420, 420-50, 420-100, 420-150, 420-200, 420-250, 420-300
Hence prize money are
₹420, ₹370, ₹320, ₹270, ₹220, ₹170, ₹120
Answered by parmeswar739
22

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