a sum of rs 190 is divided into two parts. if the smaller part is rs 5 less than half of the greater part, find the parts of the sum.
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Let the two parts of Rs.190 be x and y.
x - greater part
& y - smaller part
According to the question,
x + y = 190 ......(I)
&
y = x/2 - 5
put the value of y in eqn (I), we get
x + (x/2 - 5) = 190
=> 3x/2 = 190 + 5
=> 3x/2 = 195
=> x = 195 × 2/3
=> x = 130
from eqn (I),
130 + y = 90
=> y = 60
Hence, x = Rs. 130 & y = Rs.60
Verification :
from eqn (I),
x + y = 190
=> 130 + 60 = 190
=> 190 = 190
----------------------------Hence verified ••••
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