Question

A sum of Rs. 20,000 yielded an interest of Rs. 1200 in a year. How much interest will a

sum of Rs.35,000 yield in one year at the same rate of interest?

Answer 1

Answer :-

For the sum of Rs. 20000 :-

• P = Rs. 20000
• SI = Rs. 1200
• T = 1 year

We know that,

→ SI = P × R × T / 100

Substituting the values :-

→ 1200 = 20000 × R × 1 / 100

→ 1200 = 200R

→ R = 1200 / 200

→ R = 6

Rate of interest = 6%

Now, calculating simple interest for Rs. 35000

• P = Rs. 35000
• R = 6%
• T = 1 year

→ SI = P × R × T / 100

→ SI = 35000 × 6 × 1 / 100

→ SI = 350 × 6

→ SI = 2100

Simple interest = Rs. 2100

Answer 2

Correct Question :-

• A sum of Rs. 20,000 yielded an interest of Rs. 1,200 in a year. How much interest will a sum of Rs. 35,000 yield in one year at the same rate of interest ?

Given :-

• A sum of Rs. 20,000 yielded an interest of Rs. 1,200 in a year.

To find :-

• Find the simple interest ?

Solution :-

• The sum of Rs. 20,000

• P = Rs. 20,000
• SI = Rs, 1,200
• T = 1 year

★ As we know that,

$\dashrightarrow$ SI = $\large{\sf{\frac{P \: \times \: R \: \times \: T}{100}}}$

$~~~~~~~~~~~$ ★ Substituting the values :

:$\implies$ 1,200 = $\large{\sf{\frac{20,000 \: \times \: R \: \times \: 1}{100}}}$

$~~~~~$:$\implies$ 1,200 = ${\sf{200R}}$

$~~~~~~~~~~$:$\implies$ R = $\large{\sf{\frac{1,200}{200}}}$

$~~~~~~~~~~~~~~~$:$\implies$ ${\sf{\dfrac{\cancel{1,200}}{\cancel{200}}}}$

$~~~~~~~~~~~~~~~~~~~~$:$\implies$ $\large{\underline{\boxed{\green{\bf{R~=~6}}}}}$★

• Rate of interest = 6% $\large{\bf\green{✓}}$

★ Calculating simple interest for Rs. 35,000

• P = Rs. 35,000
• R = 6%
• T = 1 year

:$\implies$ SI = $\large{\sf{\frac{P \: \times \: R \: \times \: T}{100}}}$

$~~~~~$:$\implies$ SI = $\large{\sf{\frac{35,000 \: \times \: 6 \: \times \: 1}{100}}}$

$~~~~~~~~~~$:$\implies$ ${\sf{SI~=~350~×~6}}$

$~~~~~~~~~~~~~~~$:$\implies$ $\large{\underline{\boxed{\pink{\bf{SI~=~2,100}}}}}$★

$\large\dag$ Hence,

• Simple interest = ${\bf\underline{Rs,~2,100}}$ $\large{\bf\green{✓}}$