A sum of rs.2236 is divided among a,b,c such that a recives 25% more than c and c receives 25% les than c what is a's share in the amount
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The sum is incorrect. I am assuming that the last part of the sum reads as: "c receives 25% less than b". Please verify. The answer is a's share is 780
Step-by-step explanation:
Let a, b and c be the shares. Thus:
a+b+c = 2236
Given a receives 25% more than c means a = 1.25c or a = (5/4)*c
c receives 25% less than b means c = 0.75*b
=> c = (3/4)*b
=> b = (4/3)*c
Expressing "a" and "b" in terms of "c", we get:
(5/4)*c + (4/3)*c + c = 2236
Using 12 as the common denominator, we get:
(15c + 16c + 12c) / 12 = 2236
43c = 2236 * 12
c = 624
b = (4/3)*c = (4/3)*624 = 832
a = (5/4)*c = (5/4)*624 = 780
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