Question

A sum of rs 2387 is divided into three parts in such a way that one fifth of the first part,one half of the second part and fourth one the third part are equal. Find the sum of five times the first part,three times the second part and four times the third part (in rupees).

Answer 1

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Answer 2

Answer:

The required sum is Rs. 10199.

Step-by-step explanation:

Total amount = Rs 2387

Let the three parts be A, B, and C respectively.

The other relation is given as:

1/5 A = 1/2B = 1/4C

Now, finding values of B and C with respect to A,

2A = 5B

Hence, B = 2A/5

Again, 4A = 5C

Hence, C = 4A/5

As we know, A+ B + C = 2387

Now substituting the values of B and C here, we get:

A + 2A/5 + 4A/5 = 2387

On solving this equation, we get the value of A as 1085

Now using this value to find the values of B and C, we get:

B = 2A/5 = 434

Similarly, C = 868

Since we have got all the values, we can easily find the required sum as:

(1085*5) + (434*3)+ (868*4) = 10199.