Question

A sum of rs 2387 is divided into three parts in such a way that one fifth of the first part, one half of the second part and fourth one the third part are equal. Find the sum of five times the first part, three times the second part and four times the third part (in rupees).

Answer 1

Answer:

Step-by-step explanation:

Let sum of three parts a+b+c=2387 Rs.

By question, a/5 =b/2 =c/4 =k.

a=5k, b=2k, c=4k.

So, 5k+2k+4k=2387. 11k=2387.

k=2387/11 =217.

Now in the question,

5a+3b+4c=25k+6k+16k=47k=47*217=10,199 Rs.

Answer 2

Let us consider that sum of Rs.2387 is divided into three parts A, B and C .

According to the question,

A/5 = B/2 = C/4 = X

A = 5X

B = 2X

C = 4X

now, A+ B + C = 2387

∴ 5X + 2X + 4X = 2387

11X = 2387

X = 217

Therefore, 1st part , A = 5X = 5 × 217 = 1085

2nd part, B = 2X= 2 × 217 = 434

3rd part , C = 4X = 4 × 217 = 868

now, 5times of 1st part = 5A = 5 × 1085 = 5425

three times of 2nd part = 3B = 3 × 434 = 1302

2nd times of 3rd part = 2C = 2 × 868 = 1736

Ans:-  5times of 1st part is 5425, three times of 2nd part is 1302, and

2nd times of 3rd part is 1736