A sum of rs ₹ 2500 is distributed among x,y and z in the ratio 1/2:3/4:5/6 . what is the difference betwwen maximum share and minimum share ?
Answers
Answer:
1000&600
Step-by-step explanation:
lcm of ratio =12
≈ 6x+9x+10x=25x.
≈x=2500/25
x=100.
maximum share 10x= 10(100)=1000
&minimum share 6x= 6(100)=600.
Given : A sum of 2,500 is distributed among
X, Y and Z in the ratio 1/2 : 3/4 : 5/6
To Find : difference between the maximum share and the minimum share
Solution:
Share of X = a/2 ₹
Share of Y = 3a/4 ₹
Share of Z = 5a/6 ₹
Total Share = a/2 + 3a/4 + 5a/6
= a(6 + 9 + 10)/12
= 25a/12
25a/12 = 2500
=> a = 1200
Share of X = a/2 = 1200/2 = 600 ₹
Share of Y = 3a/4 = 3(1200)/4 = 900 ₹
Share of Z = 5a/6 = 5(1200)/6 = 1000 ₹
Maximum share = 1000
Minimum Share = 600
Difference = 1000 - 600 = 400
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