Question

A sum of Rs 2700 is to be given in the form of 63 prices .If the price of either Rs 100 or R 25, find the numbers of prices each types answer step by step

Answer 1

Answer:

100 prizes = 15

25 prizes = 48

Step-by-step explanation:

Given :

• Total sum of the prices to be given = 63

• Total amount of all prices = 2700

• They are either of denominations rs. 100 or rs. 25

To find :

• Number of prices of each type

Let number of rs. 100 prices = X

Let number of rs. 25 prices = Y

X+Y = 63 - - - (1)

Now for other condition:

100X+25Y = 2700

4X + Y = 108 - - - - (2)

(2)-(1) :

4X + Y - (X + Y) = 108-63

4X + Y - X - Y = 45

3X = 45

X = 15

Substituting the value Of X in equation 1 = 4(15)+y = 108

60+y=108

y = 48

15 rupees 100 prizes and 48 rupees 25 prizes are to be given

Answer 2

$\huge\sf\pink{Answer}$

☞ 15-100 Rupee prizes and 48-25 Rupee prizes is Yourur Answer

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ Total amount to be given = 2700

✭ Total Number of prices = 63

✭ The price is either of Rs 100 or Rs 25

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◈ Number of prices of each type

$\rule{110}1$

$\huge\sf\purple{Steps}$

Answer:

100 prizes = 15

25 prizes = 48

Step-by-step explanation:

Assume that,

◕ Number of 100 Ruppee prices as x

◕ Number of 25 Rupee prices be y

$\bullet\:\underline{\textsf{As Per the Question}}$

➢ $\sf x+y = 63\qquad -eq(1)$

And also,

➢ $\sf 100x+25y = 2700$

➢ $\sf 4x + y = 108 \qquad-eq(1)$

Subtracting eq(1) from eq(2)

➝ $\sf 4x + y - (x + y) = 108-63$

➝ $\sf 4x + y - x - y = 45$

➝ $\sf 3x = 45$

➝ $\sf\red{x = 15}$

Substituting the value of x in eq(1)

➳ $\sf 4(15)+y = 108$

➳ $\sf 60+y=108$

➳ $\sf\orange{y = 48}$

$\rule{170}3$