A sum of Rs 280 is to be used towards four prizes .If each prize after the first is Rs 20 less than its preceding prize, find the value of each of the
prizes.{ Arithmetic Progressions}.
Explain the answer.
And how common difference is taken.
Answers
Answered by
179
let amt for 1st prize=x
therefore, amt for 2nd prize = x-20
amt for 3rd prize = x-20-20 = x-40
amt for 4th prize = x-40-20 = x-60
therefore,
x+(x-20)+(x-40)+(x-60)=280
=>4x -120=280
=>x=100
therefore,
1st prize=Rs.100
2nd prize=Rs.80
3rd prize=Rs.60
4th prize=Rs.40
therefore, amt for 2nd prize = x-20
amt for 3rd prize = x-20-20 = x-40
amt for 4th prize = x-40-20 = x-60
therefore,
x+(x-20)+(x-40)+(x-60)=280
=>4x -120=280
=>x=100
therefore,
1st prize=Rs.100
2nd prize=Rs.80
3rd prize=Rs.60
4th prize=Rs.40
Answered by
37
Answer:
Step-by-step explanation:
Sum = 280
42[2n+(4−1)×20]2(2a−60)a=280=280=100
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