Question

A sum of Rs.315 consists of 25 paisa, 50 paisa and rs.1 coins in
the ratio of 3:4:6. What is the number of each kind of coin
respectively?​

Answer 1

Answer:

25 ps, 50 ps, Rel in the ratio 3:4:6

Nos=25p=3x

50 ps=4x

Re 1 = 6x

3X/4+4x/2+6x=315

multiply by 4

3x+8x +24x=1260

35x=1260

x=1260/35=36

25p=3x=108 Nos

50p=4x=144 Nos

Rel=6x=216Nos

Answer 2

There are 108 25 paise, 144 50 paise and 216 Re. 1.

Step-by-step explanation:

Since we have given that

25 paise, 50 paise and Rs. 1 coin.

Let the ratio of their numbers = 3:4:6

Let the number of 25 paise be 3x

Let the number of 50 paise be 4x

Let the number of Re. 1 coin be 6x

Amount earned 25 paise = $0.25\times 3x=0.75x$

Amount earned 50 paise = $0.50\times 4x=2x$

Amount earned Re. 1 = 6x

According to question, we get that

$0.75x+2x+6x=315\\\\8.75x=315\\\\x=\dfrac{315}{8.75}\\\\x=36$

Hence, there are $3\times 36=108$ 25 paisa, $4\times 36=144$ 50 paise and $6\times 36=216$ Re. 1.

Therefore, there are 108 25 paise, 144 50 paise and 216 Re. 1.

# learn more:

26. Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?

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