A sum of rs.45 is made up of 100 coins of 50 paise and 5 paise.how many of them are 50 paise coins
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let no. of 50 paise coins=x
no. of 5 paise coins=y
x+y=100
.50x+.05y=45
.50x+.05(100-x)=45
.50x-.05x=45-5=40
.45x=40
x=88.88
no. of 5 paise coins=y
x+y=100
.50x+.05y=45
.50x+.05(100-x)=45
.50x-.05x=45-5=40
.45x=40
x=88.88
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