Question

A sum of Rs 480 is distributed to two persons A and B in the ralo of 3:5. Find the share of A and B.​

Answer 1

Step-by-step explanation:

\text {A : B : C} = \dfrac{1}{5} : \dfrac{2}{3} : \dfrac{1}{4}A : B : C=

5

1

:

3

2

:

4

1

Make the denominators the same:

\text {A : B : C} = \dfrac{1 \times 12}{5 \times 12} : \dfrac{2 \times 20}{3 \times 20} : \dfrac{1 \times 15 }{4 \times 15}A : B : C=

5×12

1×12

:

3×20

2×20

:

4×15

1×15

\text {A : B : C} = \dfrac{12}{60} : \dfrac{40}{60} : \dfrac{15 }{60}A : B : C=

60

12

:

60

40

:

60

15

Multiply by 60 through:

\text {A : B : C} = 12: 40 : 15A : B : C=12:40:15

.

Let x be the constant ratio:

12x + 40x + 15x = 67x

.

Find 1 x:

67x = 536

Divide both sides by 67:

x = 8

.

Find each of their amount:

A = 12x = 12(8) = Rs 96

B = 40x = 40(8) = Rs 320

c = 15x = 15(8) = Rs 120

.

So the Rs 536 is divided as:

A : B : C = Rs 96 : Rs 320 : Rs 120

.

Answer: A = Rs 96 , B = Rs 320 , C = Rs 120

Answer 2

$\mathfrak{dear \:mate }$

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a+b =480

3x+5x=480

8x=480

x=480/8

x=60

so 3x=60*3=180

5x=60*5=300

so A's share =180

so B's share =300

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