A sum of rs 69300 is to be divided between two boys A and B, 21 and 22 years old respectively in such a way like if there portions be invested
at 10%p.a. compound interest, they will reach equal amounts on reaching 24 years age.
i) what is the share of each of the original money?
ii)what will each receive when 24 years old?
Answers
8th
Maths
Comparing Quantities
Compound Interest
A sum of Rs. 69,300 is to b...
MATHS
HARD
A sum of Rs. 69,300 is to be divided between two boys A and B, 21 and 22 years old respectively, in such a way that, if their portions be invested at 10 per cent per annum compound interest, they will receive equal amounts on reaching 24 years of age. What will each receive, when 24 years old?
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ANSWER
Let A's share be =Rsx
Then, B's share =Rs69,300−x
For A,
N=24−21=3years
P=Rsx
R=10 %
On interest being compounded, Amount=P(1+
100
R
)
N
=x×(1+
100
10
)
3
=x×(1.1)
3
-- (1)
For B,
N=24−22=2years
P=Rs69,300−x
R=10 %
On interest being compounded, Amount=P(1+
100
R
)
N
=(69,300−x)×(1+
100
10
)
2
=(69,300−x)×(1.1)
2
-- (2)
Given, eqn 1= eqn 2
=>x×(1.1)
3
=(69,300−x)×(1.1)
2
=>x×1.1=69,300−x
=>2.1x=69,300
=>x=33,000
Hence, A's share be =Rsx=Rs33,000
Then, John's share =Rs69,300−x=Rs36,300
Amount, A will receive when he is 24 years old =x×(1.1)
3
=33,000×(1.1)
3
=Rs43,293
Since, both receive the same amounts B will also receive Rs43,293 when he is 24 years old.
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Answer:
Step-by-step explanation:
Sum = Rs 69300
Let share of boy A be Rs x.
Then share of boy B = Rs (69300 – x)
Age of A = 21 years
∴ Time for investment for A (t1) = (24 – 21) years = 3 yrs
Age of B = 22 years
∴ Time for investment for B (t2) = (24 – 22) years = 2 yrs
Rate (r) = 10% p.a.
Now, principal for A (PA) = share of A = Rs x
Principal for B (PB) = share of B = Rs (69300 – x)
CONTINUE IN ATTACHMENT..
